Tuesday, December 22, 2009

What's the difference between covariance and assignment compatibility?

With the release of co and contra-variance support in C# 4.0, there is lot of confusion between covariance and assignment compatibility. Here I have copied an article from Eric Lippert blog on “What’s the difference between covariance and assignment compatibility”. Eric is a senior developer in C# team. So go through his post below and enjoy:

I've written a lot about this already, but I think one particular point bears repeating.

As we're getting closer to shipping C# 4.0, I'm seeing a lot of documents, blogs, and so on, attempting to explain what "covariant" means. This is a tricky word to define in a way that is actually meaningful to people who haven't already got degrees in category theory, but it can be done. And I think it's important to avoid defining a word to mean something other than its actual meaning.

A number of those documents have led with something like:

"Covariance is the ability to assign an expression of a more specific type to a variable of a less specific type. For example, consider a method M that returns a Giraffe. You can assign the result of M to a variable of type Animal, because Animal is a less specific type that is compatible with Giraffe. Methods in C# are 'covariant' in their return types, which is why when you create a covariant interface, it is indicated with the keyword 'out' -- the returned value comes 'out' of the method."

But that's not at all what covariance means. That's describing "assignment compatibility" -- the ability to assign a value of a more specific type to a storage of a compatible, less specific type is called "assignment compatibility" because the two types are compatible for the purposes of verifying legality of assignments.

So what does covariance mean then?

First off, we need to work out precisely what the adjective "covariant" applies to. I'm going to get more formal for a bit here, but try to keep it understandable.

Let's start by not even considering types. Let's think about integers. (And here I am speaking of actual mathematical integers, not of the weird behaviour of 32-bit integers in unchecked contexts.) Specifically, we're going to think about the ≤ relation on integers, the "less than or equal to" relation. (Recall that of course a "relation" is a function which takes two things and returns a bool which indicates whether the given relationship holds or does not hold.)

Now let's think about a projection on integers. What is a projection? A projection is a function which takes a single integer and returns a new integer. So, for example, z → z + z is a projection; call it D for "double".  So are z → 0 - z, N for "negate" and z → z * z, S for "square".

Now, here's an interesting question. Is it always the case that (x ≤ y) = (D(x) ≤ D(y))?  Yes, it is. If x is less than y, then twice x is less than twice y. If x is equal to y then twice x is equal to twice y. And if x is greater than y, then twice x is greater than twice y. The projection D preserves the direction of size.

What about N? Is it always the case that (x ≤ y) = (N(x) ≤ N(y))?  Clearly not. 1 ≤ 2 is true, but -1 ≤ -2 is false. But we notice that the reverse is always true!  (x ≤ y) = (N(y) ≤ N(x)). The projection N reverses the direction of size.

What about S? Is it always the case that (x ≤ y) = (S(x) ≤ S(y))? No. -1 ≤ 0 is true, but S(-1) ≤ S(0) is false. What about the opposite? Is it always the case that (x ≤ y) = (S(y) ≤ S(x)) ? Again, no. 1 ≤ 2 is true, but S(2) ≤ S(1) is false. The projection S does not preserve the direction of size, and nor does it reverse it.

The projection D is "covariant" -- it preserves the ordering relationship on integers. The projection N is "contravariant". It reverses the ordering relationship on integers. The projection S does neither; it is "invariant".

Now I hope it is more clear exactly what is covariant or contravariant. The integers themselves are not variant, and the "less than" relationship is not variant. It's the projection that is covariant or contravariant -- the rule for taking an old integer and making a new one out of it.

So now lets abandon integers and think about reference types. Instead of the ≤ relation on integers, we have the ≤ relation on reference types. A reference type X is smaller than (or equal to) a reference type Y if a value of type X can be stored in a variable of type Y. That is, if X is "assignment compatible" with Y.

Now consider a projection from types to types. Say, the projection "T goes to IEnumerable<T>".  That is, we have a projection that takes a type, say, Giraffe, and gives you back a new type, IEnumerable<Giraffe>. Is that projection covariant in C# 4?  Yes. It preserves the direction of ordering. A Giraffe may be assigned to a variable of type Animal, and therefore an sequence of Giraffes may be assigned to a variable that can hold a sequence of Animals.

We can think of generic types as "blueprints" that produce constructed types. Let's take the projection that takes a type T and produces IEnumerable<T> and simply call that projection "IEnumerable<T>". We can understand from context when we say "IEnumerable<T> is covariant" what we mean is "the projection which takes a reference type T and produces a reference type IEnumerable<T> is a covariant projection". And since IEnumerable<T> only has one type parameter, it is clear from the context that we mean that the parameter to the projection is T. After all, it is a lot shorter to say "IEnumerable<T> is covariant" than that other mouthful.

So now we can define covariance, contravariance and invariance. A generic type I<T> is covariant (in T) if construction with reference type arguments preserves the direction of assignment compatibility. It is contravariant (in T) if it reverses the direction of assignment compatibility. And it is invariant if it does neither. And by that, we simply are saying in a concise way that the projection which takes a T and produces I<T> is a covariant/contravariant/invariant projection.

Source:

http://blogs.msdn.com/ericlippert/archive/2009/11/30/what-s-the-difference-between-covariance-and-assignment-compatibility.aspx

Sunday, December 20, 2009

Just created profile on SlideShare.NET

I have just created an account on SlideShare.NET which will help me uploading and sharing presentation slides of events that take place :)

You can visit my profile on SlideShare.NET or download/view from the widget below!


SlideShare

Enjoy!!!
http://www.slideshare.net/adil.mughal/presentations

Saturday, December 12, 2009

The LINQ Way

In this post, I will be sharing some code snippets to continue emphasizing on the use of LINQ. The code is almost the same which I discussed in Emerging .NET Devs UG Meeting in Oct ‘09.

Let’s see a comparison of doing similar task with typical way and the LINQ way, in particular related to LINQ to Object, but first consider interface “ICustomer” on which we are going to play

namespace LinqToObject
{
internal interface ICustomer
{
string CustomerID { get; set; }
string CompanyName { get; set; }
string ContactName { get; set; }
string Country { get; set; }

List<Customer> GetCustomers();
}
}

Now assume there is a class Customer implementing ICustomer and what we want is to retrieve list of all customers in country “Pakistan”.

Typical Way:

public IEnumerable<ICustomer> GetCustomersFromPakistan()
{
List<ICustomer> customerList = new List<ICustomer>();
foreach (Customer c in customer.GetCustomers()) //customer is Customer:ICustomer
{
if (c.Country.StartsWith("Pakistan"))
customerList.Add(customer);
}
return customerList;
}

and it will happily print list of all customers from Pakistan

The LINQ Way:

public IEnumerable<ICustomer> GetCustomersFromPakistan()
{
var result = from c in customer.GetCustomers()
where c.Country.StartsWith("Pakistan")
select c;
return result;
}

Remarks: To be honest, it is a bit clean but nothing very impressive right?

So let’s add a further requirement, now I want all CustomersFromPakistan but ordered by Customer ID. Let’s compare the code again.

Typical Way:

public IEnumerable<ICustomer> GetCustomerFromPakistanList()
{
List<ICustomer> list = new List<ICustomer>();
foreach (ICustomer c in customer.GetCustomers())//customer is Customer:ICustomer
{
if (c.Country.Contains("Pakistan"))
{
list.Add(customer);
}
}
list.Sort(delegate(ICustomer customer1, ICustomer customer2)
{
return customer1.CustomerID.CompareTo(customer2.CustomerID);
});

return list;
}

The LINQ Way:

public IEnumerable<ICustomer> GetCustomersFromPakistan()
{
var result = from c in customer.GetCustomers()
where c.Country.Contains("Pakistan")
orderby c.CustomerID;
select c;
return result;
}

Remarks: What do you say? it’s clean and simple right!!!

Further with the use of Lambda expression, you can filter out lists easily. For instance,

ICustomer customer = new Customer();
var list = customer.GetCustomers()
.Where<ICustomer>(c=> c.Country == "Pakistan");
“Where” is an extension method and will provide you a simple way to filter sequence of values based on predicate defined using lambda expression.

Summary:

As you will come across complex conditions, for loops are really messy and LINQ provides a clean and simple way to perform object manipulation that will also improve productivity of developer. If you are still not using LINQ, I recommend you to get some hands on, you will really enjoy it.

Tuesday, December 1, 2009

Real World Scenario: Month Based Selection using AJAX Calendar Extender

Often we get requirement of enabling only month based selection in calendar control in which a calendar should display only month instead of dates or you can say a calendar that allow users to pick month only. This can be achieved by manipulating functionality of AJAX Calendar extender using JavaScript.

First, you need to set the behaviorID property of Calendar extender control and add two event handler "OnClientHidden" and "OnClientShown". For instance,

<asp:TextBox ID="txtDate" runat="server" ReadOnly="false" onfocus="AjaxDateOnFocus(this);" Width="60px" onblur="AjaxDateOnBlur(this);" />
<
cc1:CalendarExtender ID="ctxtDate" runat="server" TargetControlID="txtDate" Format="MMM-yyyy" OnClientHidden="onCalendarHidden" OnClientShown="onCalendarShown" BehaviorID="calendar1" />

Now use the following JavaScript with respective BehaviorID

function onCalendarShown() {
var cal = $find("calendar1"); //Setting the default mode to month
cal._switchMode("months", true); //Iterate every month Item and attach click event to it
if (cal._monthsBody) {
for (var i = 0; i < cal._monthsBody.rows.length; i++) {
var row = cal._monthsBody.rows[i];
for (var j = 0; j < row.cells.length; j++) {
Sys.UI.DomEvent.addHandler(row.cells[j].firstChild, "click", call);
}
}
}
}

function onCalendarHidden() {
var cal = $find("calendar1");
//Iterate every month Item and remove click event from it
if (cal._monthsBody) {
for (var i = 0; i < cal._monthsBody.rows.length; i++) {
var row = cal._monthsBody.rows[i];
for (var j = 0; j < row.cells.length; j++) {
Sys.UI.DomEvent.removeHandler(row.cells[j].firstChild, "click", call);
}
}
}
}

function call(eventElement) {
var target = eventElement.target;
switch (target.mode) {
case "month":
var cal = $find("calendar1");
cal._visibleDate = target.date;
cal.set_selectedDate(target.date);
cal._switchMonth(target.date);
cal._blur.post(true);
cal.raiseDateSelectionChanged();
break;
}
}

That’s all :) and your calendar extender will now look like

image

Enjoy!

Please note that the script is partially taken from AghaUsman.net

Note: Some of the older blog posts may show broken image links or low resolution images. This is because I mistakenly deleted the associated Picasa Web Album where images were previously uploaded. I am trying to retrieve the cached images of whatever resolution available. If you have any query, just don't hesitate to reach me via contact form